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Search: id:A047659
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| A047659 |
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Number of ways to place 3 nonattacking queens on an n X n board. |
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+0 3
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| 0, 0, 0, 0, 24, 204, 1024, 3628, 10320, 25096, 54400, 107880, 199400, 348020, 579264, 926324, 1431584, 2148048, 3141120, 4490256, 6291000, 8656860, 11721600, 15641340, 20597104, 26797144, 34479744, 43915768, 55411720
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OFFSET
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0,5
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COMMENT
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Lucas mentions that the number of ways of placing p <= n non-attacking queens on an n X n chessboard is given by a polynomial in n of degree 2p, and attribute the result to Mantel, professor in Delft. Cf. Stanley, exercise 15.
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REFERENCES
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E. Landau, Naturwissenschaftliche Wochenschrift (Aug. 2 1896).
Edouard Lucas, Recreations mathematiques, Gauthier-Villars, Paris, 1882-1894, Vol. I, p. 228.
I. Rivin, I. Vardi and P. Zimmermann, The n-queens problem, Amer. Math. Monthly, 101 (1994), 629-639.
R. P. Stanley, Enumerative Combinatorics, vol. I, exercise 15 in chapter 4 (and its solution) asks one to show the existence of a rational generating function for the number of ways of placing k non-attacking queens on an n X n chessboard.
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FORMULA
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a(n) = n(n - 2)^2(2n^3 - 12n^2 + 23n - 10)/12 if n is even, and (n - 1)(n - 3)(2n^4 - 12n^3 + 25n^2 - 14n + 1)/12 if n is odd (Landau). Also a(n) = 5a(n - 1) - 8a(n - 2) + 14a(n - 4) - 14a(n - 5) + 8a(n - 7) - 5a(n - 8) + a(n - 9) for n >= 9; g.f.: 4(9*x^4 + 35*x^3 + 49*x^2 + 21*x + 6)*x^4/((1 - x)^7*(1 + x)^2).
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CROSSREFS
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Sequence in context: A048355 A132458 A055857 this_sequence A108671 A097321 A105946
Adjacent sequences: A047656 A047657 A047658 this_sequence A047660 A047661 A047662
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KEYWORD
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nonn,easy,nice
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AUTHOR
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Paul.Zimmermann(AT)loria.fr
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EXTENSIONS
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The formula given in the Rivin et al. paper is wrong.
Entry improved by comments from Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), May 30 2001
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