0,2

A. H. Beiler, Recreations in the Theory of Numbers, Dover, N.Y., 1964, pp. 194-196.

a(n)=(4^n/4)*[(3^(n+1))+(-1)^n].

a(n)=8a(n-1)+48a(n-2); a(0)=1.

Cf. A015518.

Adjacent sequences: A053533 A053534 A053535 this_sequence A053537 A053538 A053539

Sequence in context: A131621 A003721 A075851 this_sequence A139741 A067900 A067414

easy,nonn

Barry E. Williams, Jan 15 2000