1,1

For n>2, a(n) is base at which zero is reached for the function "write f(j) in base j, read as base j+1, and then subtract 1 to give f(j+1)" starting from f(n)=2n^2-1.

a(n) =A003261(A036289(n)) =A036289(n)*A001146(n)^n-1

a(3)=3*2^(3*2^3+3)-1=3*2^27-1=402653184-1=402653183

Sequence in context: A117661 A145253 A024099 this_sequence A139299 A004818 A125538

Adjacent sequences: A056232 A056233 A056234 this_sequence A056236 A056237 A056238

nonn

Henry Bottomley (se16(AT)btinternet.com), Aug 06 2000