0,4
a(n) =3^n-2^floor[log2(3^n)] =A000244(n)-2^A056576(n)
a(3)=11 because 3^3=27 and 27-16=11
Cf. A063005.
Sequence in context: A136721 A107172 A090286 this_sequence A132092 A056705 A065706
Adjacent sequences: A056574 A056575 A056576 this_sequence A056578 A056579 A056580
nonn
Henry Bottomley (se16(AT)btinternet.com), Jun 29 2000
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