id:A056895 - OEIS Search Results

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If the smallest prime with a square excess of n is p then a(n)^2=p-n.

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	OFFSET	`1,3`
	FORMULA	`a(n) =sqrt(A056893(n)-n) =A000196(A056893(n)) =sqrt(A056894(n))`
	EXAMPLE	`a(4)=3 because the smallest prime with a square excess of 4 is 13 and 13-4=3^2`
	CROSSREFS	`Cf. A000040, A000196, A002496, A048760, A053186, A056892-A056898.` `Adjacent sequences: A056892 A056893 A056894 this_sequence A056896 A056897 A056898` `Sequence in context: A056539 A105726 A106452 this_sequence A137761 A100769 A023889`
	KEYWORD	`nonn`
	AUTHOR	`Henry Bottomley (se16(AT)btinternet.com), Jul 05 2000`

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Last modified October 12 15:26 EDT 2008. Contains 144830 sequences.

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