0,2

a(n) = n(n + 1)(2n + 1)(12n^2 + 12n + 1)/6 = 4n^5 + 10n^4 + (25/2)n^3 + (5/2)n^2 + (1/6)n = A000330(A046092(n)) - A000330(A014107(n + 1)) = A000330(A014106(n)) - A000330(A046092(n))

a(3) = 2030 = 21^2 + 22^2 + 23^2 + 24^2 = 25^2 + 26^2 + 27^2.

The n+1 consecutive squares start with the square of A014105, while the n consecutive squares start with the square of A001844.

Sequence in context: A077512 A045622 A130052 this_sequence A022749 A036071 A094190

Adjacent sequences: A059252 A059253 A059254 this_sequence A059256 A059257 A059258

nice,nonn

Henry Bottomley (se16(AT)btinternet.com), Jan 23 2001