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Search: id:A059285
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| A059285 |
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Hilbert's Hamiltonian walk projected onto the second diagonal: M'(3) (difference between sequences A059253 and A059252; their sum is A059261). |
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+0
5
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| 0, 1, 0, -1, -2, -3, -2, -1, 0, -1, 0, 1, 2, 1, 2, 3, 4, 3, 4, 5, 6, 7, 6, 5, 4, 5, 4, 3, 2, 3, 2, 1, 0, -1, 0, 1, 2, 3, 2, 1, 0, 1, 0, -1, -2, -1, -2, -3, -4, -5, -4, -3, -2, -1, -2, -3, -4, -3, -4, -5, -6, -5, -6, -7
(list; graph; listen)
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OFFSET
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0,5
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FORMULA
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Initially, M'(0)=0; recursion: M'(2n)=M'(2n-1). (-f(-M'(2n-1), 2n-1)).(-M'(2n-1)).f(-M'(2n-1), 2n-1), M'(2n+1)=M'(2n).f(M'(2n), 2n).(-M'(2n)).(-(f(M'(2n), 2n+1)). f(m, n) is the complementation to 2^n, [example: f(4 3 4 5 6 7 6 5 4 5 4 6 2 3 2 1, 3)=4 5 4 3 2 1 2 3 4 3 4 5 6 5 6 7]; (-m) is the opposite[example: m=4 5 4 3 2 1 2 3 4 3 4 5 6 5 6 7, (-m)=-4 -5 -4 -3 -2 -1 -2 -3 -4 -3 -4 -5 -6 -5 -6 -7]
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EXAMPLE
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[M'(0)=0, M'(1)=0 1 0 -1, M'(2)=0 1 0 -1 -2 -3 -2 -1 0 -1 0 1 2 1 2 3]
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CROSSREFS
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The x-projection m(3) is A059253, the y-projection m(3) is A059252 and the projection onto the first diagonal, M(3), is A059261.
Sequence in context: A119369 A122445 A165592 this_sequence A165578 A020990 A037891
Adjacent sequences: A059282 A059283 A059284 this_sequence A059286 A059287 A059288
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KEYWORD
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sign
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AUTHOR
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Claude Lenormand (claude.lenormand(AT)free.fr), Jan 24 2001
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