|
Search: id:A060886
|
|
| |
|
| 1, 1, 13, 73, 241, 601, 1261, 2353, 4033, 6481, 9901, 14521, 20593, 28393, 38221, 50401, 65281, 83233, 104653, 129961, 159601, 194041, 233773, 279313, 331201, 390001, 456301, 530713, 613873, 706441, 809101, 922561, 1047553, 1184833
(list; graph; listen)
|
|
|
OFFSET
|
0,3
|
|
|
COMMENT
|
All positive divisors of a(n) are congruent to 1, modulo 12. Proof: If p is an odd prime different from 3 then n^4 - n^2 + 1 = 0 (mod p) implies: (a) (2n^2 - 1)^2 = -3 (mod p), whence p = 1 (mod 6); and (b) (n^2 - 1)^2 = -n^2 (mod p), whence p = 1 (mod 4). - Nick Hobson Nov 13 2006
|
|
LINKS
|
Harry J. Smith, Table of n, a(n) for n=0,...,1000
|
|
PROGRAM
|
(PARI) { for (n=0, 1000, write("b060886.txt", n, " ", n^4 - n^2 + 1); ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Jul 14 2009]
|
|
CROSSREFS
|
Let Phi_k(x) be the k-th cyclotomic polynomial and form the sequence Phi_k(0), Phi_k(1), Phi_k(2), ... This gives A000027 (k=2), A002061 (k=3), A002522 (k=4), A053699 (k=5), A002061 (k=6), A053716 (k=7), A002523 (k=8), A060883 (k=9), A060884 (k=10), A060885 (k=11), A060886 (k=12), A060887 (k=13), A060888 (k=14), A060889 (k=15), A060890 (k=16), A060891 (k=18), A060892 (k=20), A060893 (k=24), A060894 (k=30), A060895 (k=32), A060896 (k=36).
Adjacent sequences: A060883 A060884 A060885 this_sequence A060887 A060888 A060889
Sequence in context: A142787 A084218 A125258 this_sequence A081586 A143008 A107963
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com), May 05 2001
|
|
|
Search completed in 0.002 seconds
|