1,1

H. Bottomley, Illustration of initial terms

a(n) =4^n/6+2^n+4/3 =(2^n+2)*(2^n+4)/6 =4*A007581(n-1) =4(a(n-1)-1)-2^n =A028400(n-1)-A002450(n-1)

Adjacent sequences: A060916 A060917 A060918 this_sequence A060920 A060921 A060922

Sequence in context: A009916 A123861 A115099 this_sequence A009333 A086912 A000585

nonn

Henry Bottomley (se16(AT)btinternet.com), Apr 10 2001