1,1
a(n) =A001232(n)/99 =A008918(n)/198.
Number of terms with k digits is A000045([n/2]). Union of this sequence and twice this sequence is A061852 and 99 times that is A008919.
Sequence in context: A083440 A138144 A090103 this_sequence A138145 A165370 A134962
Adjacent sequences: A061848 A061849 A061850 this_sequence A061852 A061853 A061854
base,nonn
Henry Bottomley (se16(AT)btinternet.com), May 10 2001
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