0,1
a(n) =A008919(n)/99.
Union of A061851 and twice A061851. Number of terms with k digits is A006355([n/2]+1).
Sequence in context: A143964 A034708 A091784 this_sequence A083511 A067894 A094620
Adjacent sequences: A061849 A061850 A061851 this_sequence A061853 A061854 A061855
base,nonn
Henry Bottomley (se16(AT)btinternet.com), May 10 2001
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