0,3

a(n) =n+a(n-1)+a(n-2)+a(n-3) =(A001590(n+4)-n-3)/2

a(5)=5+15+7+3=30

n plus sum of all previous terms gives A000225, n plus sum of two previous terms gives A001924, n plus previous term gives A000217, n gives A001477.

Cf. A007800.

Adjacent sequences: A062541 A062542 A062543 this_sequence A062545 A062546 A062547

Sequence in context: A055795 A058695 A023610 this_sequence A120411 A069112 A064084

nonn

Henry Bottomley (se16(AT)btinternet.com), Jun 26 2001