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Search: id:A062717
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| A062717 |
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Numbers n such that 6n+1 is a perfect square. |
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+0
11
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| 0, 4, 8, 20, 28, 48, 60, 88, 104, 140, 160, 204, 228, 280, 308, 368, 400, 468, 504, 580, 620, 704, 748, 840, 888, 988, 1040, 1148, 1204, 1320, 1380, 1504, 1568, 1700, 1768, 1908, 1980, 2128, 2204, 2360, 2440, 2604, 2688, 2860, 2948, 3128, 3220, 3408, 3504
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Sequence allows us to find X values of the equation: 6*X^3 + X^2 = Y^2. - Mohamed Bouhamida (bhmd95(AT)yahoo.fr), Nov 06 2007
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FORMULA
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G.f.: (4x^3+4x^2+4x)/[(1-x)(1-x^2)^2].
a(2n)=n(6n+2), a(2n+1)=6*n^2+10n+4. - Mohamed Bouhamida (bhmd95(AT)yahoo.fr), Nov 06 2007
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PROGRAM
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(PARI) je=[]; for(n=0, 7000, if(issquare(6*n+1), je=concat(je, n))); je
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CROSSREFS
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Equals 4 * A001318.
Cf. A005563, A046092, A001082, A002378, A036666.
Sequence in context: A006580 A061814 A087254 this_sequence A084922 A047185 A034733
Adjacent sequences: A062714 A062715 A062716 this_sequence A062718 A062719 A062720
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KEYWORD
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easy,nonn
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AUTHOR
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Jason Earls (zevi_35711(AT)yahoo.com), Jul 14 2001
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