1,1

229 is another term because 613^2 divides 229!+1. See A115091 for primes whose square divides m!+1 for some m. An examination of the factorizations of m!+1 for m<=100 found no additional squares. - T. D. Noe (noe(AT)sspectra.com), Mar 01 2006

562 is also a term because 562!+1 is divisible by 563^2. - Vladeta Jovovic (vladeta(AT)eunet.rs), Mar 30 2004

Comment from Francois BRUNAULT, Nov 23 2008: A web search reveals that for 1 <= n <= 228 there are 82 values of n for which n! + 1 has not been completely factored (the smallest is n=103), so showing thjat 229 and 562 are indeed the next two terms will be a huge task. I checked that n!+1 is not divisible by p^2 for n <= 1000 and prime p < 10^8.

It is very likely that 229 and 562 are the next two terms, but this has not yet been proved. - Nov 29 2008

Hisanori Mishima, Factorizations of m!+1

23 is a term because 23!+1 =47^2*79*148139754736864591.

229 and 562 are terms because

229!+1 = 613^2 * 38669 * 1685231 * 3011917759 * (417-digit composite)

562!+1 = 563^2 * 64467346976659839517037 * (1275-digit composite)

Flatten[Position[MoebiusMu[Range[30]!+1], 0]]. - T. D. Noe (noe(AT)sspectra.com), Mar 01 2006, Nov 21 2008

Cf. A115091.

Sequence in context: A112918 A138920 A048224 this_sequence A139373 A069575 A072215

Adjacent sequences: A064234 A064235 A064236 this_sequence A064238 A064239 A064240

nonn

Vladeta Jovovic (vladeta(AT)eunet.rs), Sep 22 2001

Example corrected by T. D. Noe (noe(AT)sspectra.com), Nov 26 2008