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A064618 Stirling transform of (n!)^2. +0
2
1, 1, 5, 49, 821, 21121, 775205, 38516689, 2490976661, 203419086241, 20474978755205, 2490729330118129, 360263844701062901, 61114158974786823361, 12017074366801186956005 (list; graph; listen)
OFFSET

0,3

COMMENT

Comments from Thomas Wieder (wieder.thomas(AT)t-online.de), Oct 21 2004: "Also the number of hierarchies with labeled elements and labeled levels where the levels are permuted. Let l_x denote level x, e.g. l_2 is level 2. Let 1 denote an element and 2 a second element and so on. Then l_1:123 means elements 1,2 and 3 are on level 1.

"Let | indicate separation between levels. Then l_1:1|l_2:346|l_3:5 denotes a hierarchy of n=6 unlabeled elements with element 1 on level 1, elements 3,4 and 6 on level 2 and element 5 on level 3.

"E.g. for n=3 one has a(3) = 49 possible hierarchies:

"l_1:123,

"l_1:12|l_2:3, l_1:13|l_2:2, l_1:23|l_2:1,

"l_2:12|l_1:3, l_2:13|l_1:2, l_2:23|l_1:1,

"l_1:1|l_2:23, l_1:2|l_2:13, l_1:3|l_2:12,

"l_2:1|l_1:23, l_2:2|l_1:13, l_2:3|l_1:12,

"l_1:1|l_2:2|l_3:3 and further five permutations of the elements with levels fixed,

"l_3:1|l_1:2|l_2:3 and further five permutations of the elements with levels fixed,. etc., up to

"l_3:1|l_2:2|l_1:3 and further five permutations of the elements with levels fixed. this gives 1 + 6 +6 + 6*6 = 49 = a(3) possible hierarchies.

"See A001339 for the number of hierarchies with unlabeled elements and labeled levels."

LINKS

Thomas Wieder, Home Page.

Thomas Wieder, (Old) Home Page.

FORMULA

a(n)=sum(stirling2(n, k)*((k!)^2), k=0..n), n=0, 1, 2...

E.g.f: hypergeom([1, 1], [], exp(x)-1). - Vladeta Jovovic (vladeta(AT)eunet.rs), Sep 14 2003

CROSSREFS

Cf. A001044.

Cf. A001339.

Sequence in context: A104600 A002111 A001819 this_sequence A075986 A084765 A082795

Adjacent sequences: A064615 A064616 A064617 this_sequence A064619 A064620 A064621

KEYWORD

nonn

AUTHOR

Karol A. Penson (penson(AT)lptl.jussieu.fr), Sep 26 2001

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Last modified November 25 20:09 EST 2009. Contains 167514 sequences.


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