|
Search: id:A065075
|
|
|
| A065075 |
|
Sum of digits of the sum of the preceding numbers. |
|
+0 13
|
|
| 1, 1, 2, 4, 8, 7, 5, 10, 11, 13, 8, 7, 14, 10, 2, 4, 8, 7, 5, 10, 11, 13, 8, 16, 14, 19, 11, 13, 8, 7, 14, 10, 11, 13, 8, 7, 5, 10, 11, 13, 17, 16, 14, 10, 11, 13, 8, 16, 14, 19, 20, 13, 8, 16, 14, 19, 20, 13, 8, 16, 14, 19, 20, 22, 17, 16, 14, 19, 20, 13, 17, 16, 14, 19, 20, 13
(list; graph; listen)
|
|
|
OFFSET
|
1,3
|
|
|
COMMENT
|
Same digital roots as A004297 (a(1) = 1, a(n) = sum of digits of all previous terms) and A001370 (Sum of digits of 2^n)); they end in the cycle {1 2 4 8 7 5}. - Alexandre Wajnberg (alexandre.wajnberg(AT)skynet.be), Dec 11 2005
The missing numbers are precisely the multiples of 3. - Alexandre Wajnberg (alexandre.wajnberg(AT)skynet.be), Dec 28 2005
|
|
FORMULA
|
a(1) = 1, a(2) = 1, a(n) = sum of digits of (a(1)+a(2)+...+a(n-1)).
|
|
EXAMPLE
|
a(6) = 7 because a(1)+a(2)+a(3)+a(4)+a(5) = 16 and 7 = 1+6
|
|
PROGRAM
|
(PARI): digitsum(n) = local(v, d); v=[]; while(n>0, d=divrem(n, 10); n=d[1]; v=concat(v, d[2])); sum(j=1, matsize(v)[2], v[j]) a065075(m) = local(a, j, s); a=1; print1(a, ", "); s=a; for(j=1, m, a=digitsum(s); print1(a, ", "); s=s+a) a065075(80)
|
|
CROSSREFS
|
Sequence in context: A071571 A029898 A021406 this_sequence A001370 A039794 A113417
Adjacent sequences: A065072 A065073 A065074 this_sequence A065076 A065077 A065078
|
|
KEYWORD
|
nonn,base,easy
|
|
AUTHOR
|
Bodo Zinser (BodoZinser(AT)Compuserve.com), Nov 09 2001
|
|
EXTENSIONS
|
More terms from Larry Reeves (larryr(AT)acm.org) and Klaus Brockhaus (klaus-brockhaus(AT)t-online.de), Nov 13 2001
|
|
|
Search completed in 0.002 seconds
|