1,1
A000330(m)+2 gives primes.
821 = 2 + (1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 + 100 + 121 + 144 + 169) = 2 + 919 = c + Sum[k^2;1...13]. Instead of c = 2 several other constants give numerous solutions.
Cf. A000330, A065245.
Sequence in context: A056801 A092568 A055624 this_sequence A012844 A104052 A062625
Adjacent sequences: A065241 A065242 A065243 this_sequence A065245 A065246 A065247
nonn
Labos E. (labos(AT)ana.sote.hu), Oct 24 2001
Search completed in 0.002 seconds