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A065566 Numbers n such that floor((5/4)^(n+1))/floor((5/4)^n)=5/4. +0
2
7, 15, 17, 21, 25, 34, 52, 56, 59, 68, 74, 78, 99, 104, 111, 117, 118, 119, 124, 127, 129, 135, 136, 141, 145, 157, 162, 172, 179, 181, 184, 189, 190, 203, 204, 206, 209, 211, 212, 222, 226, 228, 245, 247, 250, 256, 258, 283, 291, 302, 315, 318, 327, 328, 331 (list; graph; listen)
OFFSET

1,1

COMMENT

Also, numbers n such that (5^(n+1) mod 4^(n+1))/(5^n mod 4^n)=5, or A138589(n+1)/A138589(n)=5. (See the Mathar link in A139768.)

LINKS

Zak Seidov, Table of n, a(n) for n = 1..1000.

FORMULA

Is it true that lim n --> infinity a(n)/n = 6 ?

PROGRAM

(PARI): for(n=1, 700, if(floor((5/4)^(n+1))/floor((5/4)^n)==5/4, print1(n, ", ")))

(PARI) { n=0; f=5/4; for (m=1, 10^9, if ((floor(f^(m + 1))/floor(f^m)) == f, write("b065566.txt", n++, " ", m); if (n==1000, return)) ) } [From Harry J. Smith (hjsmithh(AT)sbcglobal.net), Oct 22 2009]

CROSSREFS

Cf. A065554, A138589, A139768.

Sequence in context: A070407 A069841 A076401 this_sequence A154618 A138641 A115783

Adjacent sequences: A065563 A065564 A065565 this_sequence A065567 A065568 A065569

KEYWORD

nonn

AUTHOR

Benoit Cloitre (benoit7848c(AT)orange.fr), Nov 30 2001

EXTENSIONS

More terms from Jason Earls (zevi_35711(AT)yahoo.com), Dec 03 2001

Edited by N. J. A. Sloane (njas(AT)research.att.com), May 24 2008

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Last modified November 27 22:38 EST 2009. Contains 167602 sequences.


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