id:A066508 - OEIS Search Results

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Floor[ sum 1..n (1/i)^(1/i)].

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	OFFSET	`1,3`
	COMMENT	`Floor(Sum[(1/i)^(1/i), {i=1 to n}]) = Floor(Sum[(i)^(-1/i), {i=1 to n}]).`
	FORMULA	`Floor( H(n)^H(n) ) where H(n) is the n-th Harmonic number = A001008/A002805.`
	EXAMPLE	`For a(5), (1 + 1/2 + 1/3 + 1/4 + 1/5)^(1 + 1/2 + 1/3 + 1/4 + 1/5) ~= 6.5876918. Therefore a(5) = 6.`
	MATHEMATICA	`Table[ Floor[ Sum[ (1/i)^(1/i), {i, 1, n} ]], {n, 1, 75} ]`
	CROSSREFS	`Cf. A067054.` `Sequence in context: A093700 A118168 A083920 this_sequence A053207 A138467 A127036` `Adjacent sequences: A066505 A066506 A066507 this_sequence A066509 A066510 A066511`
	KEYWORD	`nonn`
	AUTHOR	`Robert G. Wilson v (rgwv(AT)rgwv.com), Jan 04 2002`

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Last modified December 5 23:38 EST 2009. Contains 170428 sequences.

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