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Search: id:A067813
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| A067813 |
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Start of a record-breaking run of consecutive integers with a number of prime factors (counted with multiplicity) equal to 3. |
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+0
10
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OFFSET
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1,1
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EXAMPLE
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a(4)=602 because 602 is the start of a record breaking run of 5 consecutive integers (602 to 606) each having 3 prime factors; i.e. bigomega(n)=A001222(n)=3 for n = 602, ..., 606.
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MATHEMATICA
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bigomega[n_] := Plus@@Last/@FactorInteger[n]; For[n=1; m=l=0, True, n++, If[bigomega[n]==3, l++, If[l>m, m=l; Print[n-l, " ", l]]; l=0]]
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CROSSREFS
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Cf. A067814, A067820, A067821, A067822.
Sequence in context: A133042 A056570 A066963 this_sequence A118720 A029786 A029792
Adjacent sequences: A067810 A067811 A067812 this_sequence A067814 A067815 A067816
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KEYWORD
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fini,full,nonn
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AUTHOR
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Shyam Sunder Gupta (guptass(AT)rediffmail.com), Feb 07 2002
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EXTENSIONS
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Edited by Dean Hickerson (dean(AT)math.ucdavis.edu), Jul 31 2002
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