id:A068508 - OEIS Search Results

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a(n)=round[(a(n-1)+a(n-2))/a(n-3)] starting with a(1)=a(2)=a(3)=1.

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1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1, 1, 1, 2, 3, 5, 4, 3, 1 (list; graph; listen)

	OFFSET	`1,4`
	COMMENT	`While this sequence has period 8, the unrounded version b(n)=(b(n-1)+b(n-2))/b(n-3) seems to have a quasi-period of about 8.7 for this particular starting point.` `Terms of the simple continued fraction of 1198/[sqrt(5368485)-1563]. [From Paolo P. Lava (ppl(AT)spl.at), Aug 06 2009]`
	FORMULA	`a(n)=a(n-8)` `a(n)=1/56{19(n mod 8)+12[(n+1) mod 8]+12[(n+2) mod 8]-9[(n+3) mod 8]-2[(n+4) mod 8]-2[(n+5) mod 8]+5[(n+6) mod 8]+5*[(n+7) mod 8]} with n>=0 - Paolo P. Lava (ppl(AT)spl.at), Nov 27 2006`
	EXAMPLE	`a(7)=round[(a(6)+a(5))/a(4)]=round[(5+3)/2]=4`
	CROSSREFS	`Cf. A048112.` `Sequence in context: A060444 A152814 A021981 this_sequence A137403 A082233 A058981` `Adjacent sequences: A068505 A068506 A068507 this_sequence A068509 A068510 A068511`
	KEYWORD	`nonn`
	AUTHOR	`Henry Bottomley (se16(AT)btinternet.com), Mar 25 2002`

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Last modified December 11 12:57 EST 2009. Contains 170656 sequences.

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