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Search: id:A069494
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| A069494 |
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Numbers n such that (reversal(n))^3 = reversal(n^3). Ignore leading 0's. |
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+0
1
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| 1, 2, 7, 10, 11, 20, 70, 100, 101, 110, 111, 200, 700, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 2000, 7000, 10000, 10001, 10010, 10011, 10100, 10101, 10110, 11000, 11001, 11010, 11011, 11100, 20000, 70000, 100000
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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For an arithmetical function f, call the arguments n such that f(reverse(n)) = reverse(f(n)) the "palinpoints" of f. This sequence is the sequence of palinpoints of f(n) = n^3.
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EXAMPLE
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Let f(n) = n^3. Then f(1011) = 1033364331, f(1101) = 1334633301, so f(reverse(1011)) = reverse(f(1011)). Therefore 1011 belongs to the sequence.
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MATHEMATICA
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rev[n_] := FromDigits[Reverse[IntegerDigits[n]]]; f[n_] := n^3; Select[Range[10^5], f[rev[ # ]] == rev[f[ # ]] &]
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CROSSREFS
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Sequence in context: A050596 A045266 A108493 this_sequence A134712 A030344 A029904
Adjacent sequences: A069491 A069492 A069493 this_sequence A069495 A069496 A069497
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KEYWORD
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base,nonn
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AUTHOR
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Joseph L. Pe (joseph_l_pe(AT)hotmail.com), Apr 15 2002
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