|
Search: id:A071139
|
|
|
| A071139 |
|
Numbers n such that sum of distinct primes dividing n is divisible by largest prime dividing n. |
|
+0 11
|
|
| 2, 3, 4, 5, 7, 8, 9, 11, 13, 16, 17, 19, 23, 25, 27, 29, 30, 31, 32, 37, 41, 43, 47, 49, 53, 59, 60, 61, 64, 67, 70, 71, 73, 79, 81, 83, 89, 90, 97, 101, 103, 107, 109, 113, 120, 121, 125, 127, 128, 131, 137, 139, 140, 149, 150, 151, 157, 163, 167, 169, 173, 179, 180
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
FORMULA
|
A008472(n)/A006530(n) is integer.
|
|
EXAMPLE
|
Primes and prime powers are here. Various other composite solutions: 30=2.3.5, sum=10 is divisible by 5, quotient=2; 2181270=2.3.5.7.13.17.47, sum=47 is divisible by 47, quotient=1; if n is here then all multiples of n is also here which have no other prime-factors than n has. E.g. 286, 572, 3146 are equally suitable terms; if n=2pq, where p and q are twin primes then sum=p+q+2=2q is divisible by q, the largest prime factor so 2*A037074 is a subsequence.
|
|
MATHEMATICA
|
ffi[x_] := Flatten[FactorInteger[x]] lf[x_] := Length[FactorInteger[x]] ba[x_] := Table[Part[ffi[x], 2*w-1], {w, 1, lf[x]}] sb[x_] := Apply[Plus, ba[x]] ma[x_] := Part[Reverse[Flatten[FactorInteger[x]]], 2] Do[s=sb[n]/ma[n]; If[IntegerQ[s], Print[{n, ba[n]}]], {n, 2, 1000000}]
|
|
CROSSREFS
|
Cf. A008472, A006530, A000961, A025475, A037074.
Sequence in context: A030230 A089352 A086486 this_sequence A046686 A137944 A087441
Adjacent sequences: A071136 A071137 A071138 this_sequence A071140 A071141 A071142
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Labos E. (labos(AT)ana.sote.hu), May 13 2002
|
|
|
Search completed in 0.002 seconds
|