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COMMENT
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It is unknown whether a circular permutation of the numbers 1 to n exists such that the sum of any two consecutive numbers is a cube.
According to Rivera's Puzzle 311, the smallest n for which a cubic loop exists is 473. - T. D. Noe (noe(AT)sspectra.com), Nov 26 2007
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EXAMPLE
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There is only one possible square loop of minimum length, which is: (32, 4, 21, 28, 8, 1, 15, 10, 26, 23, 2, 14, 22, 27, 9, 16, 20, 29, 7, 18, 31, 5, 11, 25, 24, 12, 13, 3, 6, 30, 19, 17) so a(32)=1.
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