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Search: id:A072070
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| A072070 |
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Number of integer solutions to the equation 4x^2+y^2+8z^2=n. |
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+0
9
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| 1, 2, 0, 0, 4, 4, 0, 0, 6, 6, 0, 0, 8, 12, 0, 0, 12, 8, 0, 0, 8, 8, 0, 0, 8, 14, 0, 0, 16, 4, 0, 0, 6, 16, 0, 0, 12, 20, 0, 0, 24, 8, 0, 0, 8, 20, 0, 0, 24, 18, 0, 0, 24, 12, 0, 0, 0, 16, 0, 0, 16, 20, 0, 0, 12, 8, 0, 0, 16, 16, 0, 0, 30, 32, 0, 0, 24, 16, 0, 0, 24, 18, 0, 0, 16, 24, 0, 0, 24, 16
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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Related to primitive congruent numbers A006991.
Assuming the Birch and Swinnerton-Dyer conjecture, the even number 2n is a congruent number if it is square-free and a(n) = 2 A072071(n).
Euler transform of period 32 sequence [2,-3,2,1,2,-3,2,-2,2,-3,2,1,2,-3,2,-5,2,-3,2,1,2,-3,2,-2,2,-3,2,1,2,-3,2,-3,...].
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REFERENCES
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J. B. Tunnell, A classical diophantine problem and modular forms of weight 3/2, Invent. Math., 72 (1983), 323-334.
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LINKS
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T. D. Noe, Table of n, a(n) for n=0..10000
Clay Mathematics Institute, The Birch and Swinnerton-Dyer Conjecture
Department of Pure Maths., Univ. Sheffield, Pythagorean triples and the congruent number problem
Karl Rubin, Elliptic curves and right triangles
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EXAMPLE
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a(4) = 4 because (1,0,0), (-1,0,0), (0,2,0) and (0,-2,0) are solutions.
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MATHEMATICA
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maxN=128; soln3=Table[0, {maxN/2}]; xMax=Ceiling[Sqrt[maxN/8]]; yMax=Ceiling[Sqrt[maxN/2]]; zMax=Ceiling[Sqrt[maxN/16]]; Do[n=4x^2+y^2+8z^2; If[n>0&&n<=maxN/2, s=8; If[x==0, s=s/2]; If[y==0, s=s/2]; If[z==0, s=s/2]; soln3[[n]]+=s], {x, 0, xMax}, {y, 0, yMax}, {z, 0, zMax}]
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PROGRAM
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(PARI) a(n)=local(X); if(n<0, 0, X=x+x*O(x^n); polcoeff(eta(X)^-2*eta(X^2)^5*eta(X^4)^-4*eta(X^8)^3*eta(X^16)^3*eta(X^32)^-2, n))
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CROSSREFS
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Cf. A006991, A003273, A072068, A072069, A072071.
Sequence in context: A134014 A072071 A045836 this_sequence A137828 A137830 A137505
Adjacent sequences: A072067 A072068 A072069 this_sequence A072071 A072072 A072073
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KEYWORD
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nonn
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AUTHOR
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T. D. Noe (noe(AT)sspectra.com), Jun 13 2002
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