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Search: id:A072290
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| 1, 11, 192, 2893, 38894, 488895, 5888896, 68888897, 788888898, 8888888899, 98888888900, 1088888888901, 11888888888902, 128888888888903, 1388888888888904, 14888888888888905, 158888888888888906
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OFFSET
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1,2
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COMMENT
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In writing out all numbers 1 through 10^n inclusive, exactly a(n+1) digits are used, of which a(n) are 0's and there are n*10^(n-1) of each of the other digits, with still an extra one for 1's.
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REFERENCES
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J. D. E. Konhauser et al., Which Way Did The Bicycle Go? Problem 134:"Digit Counting" pp. 40; 173-4 Dolciani Math. Exp. No. 18 MAA Washington DC 1996.
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FORMULA
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a(n+1) = a(n) + 9*n*10^(n-1) + 1.
a(n) = n + A053541(n) - A002275(n) = n + A033713(n). - Lekraj Beedassy (blekraj(AT)yahoo.com), Sep 16 2006
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PROGRAM
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(PARI) for(n=1, 23, print1(10^(n-1)*n+n-10^n/9+1/9" "))
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CROSSREFS
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Cf. A078427.
Sequence in context: A002195 A068649 A158509 this_sequence A112127 A142996 A105124
Adjacent sequences: A072287 A072288 A072289 this_sequence A072291 A072292 A072293
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KEYWORD
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nonn
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AUTHOR
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Lekraj Beedassy (blekraj(AT)yahoo.com), Jul 11 2002
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EXTENSIONS
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More terms from Jason Earls (zevi_35711(AT)yahoo.com), Dec 18 2002
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