1,2
Since a k-th exponent prime power has exactly k+1 divisors, choosing k=p-1, where p is a prime, thus implies a(p-1)=p for any prime p.
Sequence in context: A162414 A071107 A146072 this_sequence A064234 A037102 A042169
Adjacent sequences: A073046 A073047 A073048 this_sequence A073050 A073051 A073052
more,nice,nonn
Lekraj Beedassy (blekraj(AT)yahoo.com), Aug 31 2002
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