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Search: id:A073095
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| A073095 |
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Numbers n such that the final nonzero digit of n! is the same as the last digit of C(2n,n) (in base 10). |
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+0
1
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| 5, 12, 26, 31, 35, 51, 56, 60, 136, 152, 157, 177, 182, 252, 257, 275, 280, 287, 300, 305, 312, 627, 632, 650, 655, 662, 675, 680, 687, 751, 756, 760, 786, 811, 886, 902, 907, 927, 932, 1251, 1256, 1260, 1286, 1311, 1377, 1382, 1400, 1405, 1412, 1425
(list; graph; listen)
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OFFSET
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1,1
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FORMULA
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n such that A008904(n) = C(2n, n) reduced (mod 10)
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EXAMPLE
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12! = 479001600 C(24,12)= 2704156 and the last nonzero digit of 12! is the same as the last digit of C(24,12) hence 12 is in the sequence.
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CROSSREFS
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Sequence in context: A086168 A108201 A038254 this_sequence A078517 A128439 A145768
Adjacent sequences: A073092 A073093 A073094 this_sequence A073096 A073097 A073098
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KEYWORD
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base,easy,nonn
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AUTHOR
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Benoit Cloitre (benoit7848c(AT)orange.fr), Aug 18 2002
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