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Search: id:A073128
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| 0, 1, 1, 5, 5, 49, 118, 121, 2406, 2698, 4182, 4946, 153627, 3087192, 8203485
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OFFSET
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1,4
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FORMULA
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a(n)=Sum[cototient[j], j=1..A063896(n)]/A063896(n)
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EXAMPLE
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n=15, A063896(15)=41846733, sum of first 41846733 cototients is s=343289046464505, a(15)=s/41846733. Only in knowledge of either this quotients or of partial sums of cototients is possible to continue A063896 without recomputing previous terms!
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CROSSREFS
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Cf. A051953, A000010, A002088, A048920, A000217, A050226.
Sequence in context: A099757 A030047 A065238 this_sequence A009390 A009334 A129358
Adjacent sequences: A073125 A073126 A073127 this_sequence A073129 A073130 A073131
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KEYWORD
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more,nonn
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AUTHOR
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Labos E. (labos(AT)ana.sote.hu), Jul 16 2002
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