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Search: id:A073360
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| A073360 |
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Nested floor product of n and fractions (k+1)/k for all k>0 (mod 3), divided by 3. |
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+0
5
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| 1, 4, 9, 20, 29, 44, 69, 104, 121, 180, 241, 284, 349, 420, 521, 664, 701, 860, 1009, 1184, 1301, 1540, 1789, 1964, 2181
(list; graph; listen)
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OFFSET
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1,2
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FORMULA
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a(n)=(1/3)[...[[[[n(2/1)](3/2)](5/4)](6/5)]...(k+1)/k]..., k>0 (mod 3), where [x] = floor of x; this infinite nested floor product will eventually level-off at a(n).
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EXAMPLE
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a(2) = 4 since (1/3)[[[[[[2(2/1)](3/2)](5/4)](6/5)](8/7)](9/8)](11/10)](12/11)] = (1/3)[[[[[4(3/2)](5/4)](6/5)](8/7)](9/8)](11/10)](12/11)] = (1/3)[[[[6(5/4)](6/5)](8/7)](9/8)](11/10)](12/11)] = (1/3)[[[[7(6/5)](8/7)](9/8)](11/10)](12/11)] = (1/3)[[[[8(8/7)](9/8)](11/10)](12/11)] = (1/3)[[[[9(9/8)](11/10)](12/11)] = (1/3)[[[[10(11/10)](12/11)] = 4
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CROSSREFS
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Cf. A073359.
Adjacent sequences: A073357 A073358 A073359 this_sequence A073361 A073362 A073363
Sequence in context: A053807 A066109 A030734 this_sequence A075385 A048150 A066186
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KEYWORD
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easy,nonn
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AUTHOR
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Paul D. Hanna (pauldhanna(AT)juno.com), Jul 29 2002
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