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Search: id:A073533
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| A073533 |
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Let x(1)=1, x(n+1) = (4/3)*x(n) - floor((4/3)*x(n)); then a(n)=x(n)*3^n. |
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+0
1
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| 1, 4, 16, 64, 13, 52, 208, 832, 3328, 13312, 53248, 212992, 851968, 3407872, 13631488, 11479231, 45916924, 183667696, 734670784, 2938683136, 1294379341, 5177517364, 20710069456, 82840277824, 331361111296, 1325444445184
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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It seems that the sequence x(n) = a(n)/3^n which verifies 0<x(n)<1 is not equidistributed in (0,1) and perhaps lim n -> infinity sum(k=1,n,x(k))/n = C < 0.38 < 1/2
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FORMULA
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It appears that a(n) = 13*4^(n-5) for n > 4. - Creighton Dement (creighton.k.dement(AT)uni-oldenburg.de), Nov 04 2004
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CROSSREFS
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Cf. A058842.
Sequence in context: A119376 A022030 A135450 this_sequence A061283 A001264 A114399
Adjacent sequences: A073530 A073531 A073532 this_sequence A073534 A073535 A073536
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KEYWORD
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easy,nonn
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AUTHOR
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Benoit Cloitre (benoit7848c(AT)orange.fr), Aug 27 2002
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