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A075835 Numbers n such that 13*n^2 + 4 is a square. +0
1
0, 3, 33, 360, 3927, 42837, 467280, 5097243, 55602393, 606529080, 6616217487, 72171863277, 787274278560, 8587845200883, 93679022931153, 1021881407041800, 11147016454528647, 121595299592773317 (list; graph; listen)
OFFSET

1,2

COMMENT

Lim. n-> Inf. a(n)/a(n-1) = (11 + Sqrt(13))/2.

REFERENCES

A. H. Beiler, "The Pellian", ch. 22 in Recreations in the Theory of Numbers: The Queen of Mathematics Entertains. Dover, New York, New York, pp. 248-268, 1966.

L. E. Dickson, History of the Theory of Numbers, Vol. II, Diophantine Analysis. AMS Chelsea Publishing, Providence, Rhode Island, 1999, p. 341-400.

Peter G. L. Dirichlet, Lectures on Number Theory (History of Mathematics Source Series, V. 16); American Mathematical Society, Providence, Rhode Island, 1999, p. 139-147.

LINKS

Index entries for sequences related to linear recurrences with constant coefficients

Tanya Khovanova, Recursive Sequences

J. J. O'Connor and E. F. Robertson, Pell's Equation

Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics.

FORMULA

a(n) = [(11 + 3*Sqrt(13))^n - (11 - 3*Sqrt(13))^n] / [(2^n) * Sqrt(13)]

a(n)=11*a(n-1)-a(n-2)with a(1)=0 and a(2)=3. G.f.: 3x^2/(1-11x+x^2). [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Nov 17 2008]

CROSSREFS

Sequence in context: A121515 A002277 A001507 this_sequence A077698 A080488 A082778

Adjacent sequences: A075832 A075833 A075834 this_sequence A075836 A075837 A075838

KEYWORD

nonn

AUTHOR

Gregory V. Richardson (omomom(AT)hotmail.com), Oct 14 2002

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Last modified December 15 00:47 EST 2009. Contains 170825 sequences.


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