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Search: id:A075894
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| A075894 |
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Average of four successive primes squared, (prime(n)^2+prime(n+1)^2+prime(n+2)^2+prime(n+3)^2)/4, n>=2. |
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+0
1
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| 51, 91, 157, 235, 337, 505, 673, 925, 1213, 1465, 1777, 2137, 2587, 3055, 3625, 4183, 4645, 5275, 5875, 6595, 7615, 8605, 9535, 10417, 11035, 11677, 13057, 14485, 16207, 17845, 19363, 20773, 22243, 24055, 25477, 27259, 29107, 30655, 32803
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OFFSET
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2,1
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COMMENT
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Unlike the average of four successive primes, the average of four successive primes squared is (apparently) integer for all n>=2.
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FORMULA
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(prime(n)^2+prime(n+1)^2+prime(n+2)^2+prime(n+3)^2)/4, n>=2.
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EXAMPLE
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a(2)=51 because (prime(2)^2+prime(3)^2+prime(4)^2+prime(5)^2)/4=(3^2+5^2+7^2+11^2)/4=51.
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CROSSREFS
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Sequence in context: A039474 A020180 A049328 this_sequence A044140 A044521 A160847
Adjacent sequences: A075891 A075892 A075893 this_sequence A075895 A075896 A075897
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KEYWORD
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easy,nonn
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AUTHOR
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Zak Seidov (zakseidov(AT)yahoo.com), Oct 17 2002
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