1,5

a(n)=(a(n-2)+a(n-3))*a(n-1)/a(n-4), n>4. a(1)=a(2)=a(3)=a(4)=1.

Cf. A078918.

a(n+1)/a(n)=A079069(n).

Sequence in context: A005831 A137160 A013207 this_sequence A085864 A060935 A114903

Adjacent sequences: A078916 A078917 A078918 this_sequence A078920 A078921 A078922

nonn

Benoit Cloitre (benoit7848c(AT)orange.fr), Dec 13 2002