|
Search: id:A079278
|
|
|
| A079278 |
|
Define b by b(1) = 1 and for n>1, b(n) = b(n-1)+1/(1+1/b(n-1)); sequence gives denominator of b(n). |
|
+0
7
|
|
| 1, 2, 10, 310, 363010, 594665194510, 1871071000515058250871610, 21362861761506953021644584296874581450310229239910
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
REFERENCES
|
Suggested by Leroy Quet Feb 14 2003.
|
|
LINKS
|
Leroy Quet, Home Page (listed in lieu of email address)
|
|
FORMULA
|
Conjecture (Quet): a(m+1) = a(m)^2 + a(m)^3 /a(m-1)^2 - a(m)a(m-1)^2 for m >= 2.
|
|
EXAMPLE
|
The b sequence begins 1, 3/2, 21/10, 861/310, 1275141/363010, 2551762438701/594665194510, ...
|
|
MAPLE
|
b := proc(n) option remember; if n=1 then 1 else b(n-1)+1/(1+1/b(n-1)); fi; end;
|
|
CROSSREFS
|
Cf. A079269, A080581, A080582.
Sequence in context: A073834 A111837 A092123 this_sequence A015178 A013034 A059723
Adjacent sequences: A079275 A079276 A079277 this_sequence A079279 A079280 A079281
|
|
KEYWORD
|
nonn,frac
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com), Feb 16 2003
|
|
EXTENSIONS
|
The next term is too large to include.
|
|
|
Search completed in 0.002 seconds
|
