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Search: id:A079878
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| A079878 |
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a(1)=1, then a(n)=2*a(n-1) if 2*a(n-1)<=n, a(n)=2*a(n-1)-n otherwise. |
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+0
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| 1, 2, 1, 2, 4, 2, 4, 8, 7, 4, 8, 4, 8, 2, 4, 8, 16, 14, 9, 18, 15, 8, 16, 8, 16, 6, 12, 24, 19, 8, 16, 32, 31, 28, 21, 6, 12, 24, 9, 18, 36, 30, 17, 34, 23, 46, 45, 42, 35, 20, 40, 28, 3, 6, 12, 24, 48, 38, 17, 34, 7, 14, 28, 56, 47, 28, 56, 44, 19, 38, 5, 10, 20, 40, 5, 10, 20, 40, 1, 2
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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For n=1, 2, 8, 32, 46, 392, 12230, .... we have a(n)=n. For n=1, 3, 79, 235, 431, 1503, 2943, 6059, 6619, ... we have a(n)=1. Memo: these should be submitted as separate sequences. - njas
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FORMULA
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It seems that sum(k=1, n, a(k))/n^2 ->1/4
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PROGRAM
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(PARI) a=1; for(n=2, 100, b=if(sign(2*a-n)-1, 2*a, 2*a-n); a=b; print1(b, ", "))
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CROSSREFS
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A064434(n) + 1.
Adjacent sequences: A079875 A079876 A079877 this_sequence A079879 A079880 A079881
Sequence in context: A099500 A120253 A060547 this_sequence A137406 A120855 A091173
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KEYWORD
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nonn
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AUTHOR
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Benoit Cloitre (benoit7848c(AT)orange.fr), Feb 20 2003
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