|
Search: id:A080233
|
|
|
| A080233 |
|
Triangle T(n,k) obtained by taking differences of consecutive pairs of row elements of Pascal's triangle A007318. |
|
+0 3
|
|
| 1, 1, 0, 1, 1, -1, 1, 2, 0, -2, 1, 3, 2, -2, -3, 1, 4, 5, 0, -5, -4, 1, 5, 9, 5, -5, -9, -5, 1, 6, 14, 14, 0, -14, -14, -6, 1, 7, 20, 28, 14, -14, -28, -20, -7, 1, 8, 27, 48, 42, 0, -42, -48, -27, -8
(list; graph; listen)
|
|
|
OFFSET
|
0,8
|
|
|
COMMENT
|
Row sums are 1,1,1,1,1,1 with G.f. 1/(1-x) Can also be obtained from triangle A080232 by taking sums of pairs of consecutive row elements
Mirror image of triangle in A156644. [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Feb 14 2009]
|
|
FORMULA
|
T(n, k) = if(k>n, 0, binomial(n, k)-binomial(n, k-1))
|
|
EXAMPLE
|
Rows are {1}, {1,0}, {1,1,-1}, {1,2,0,-2}, {1,3,2,-2,-3}, ...
|
|
CROSSREFS
|
Cf. A007318, A080232.
Sequence in context: A029221 A029183 A138110 this_sequence A156644 A097808 A114325
Adjacent sequences: A080230 A080231 A080232 this_sequence A080234 A080235 A080236
|
|
KEYWORD
|
easy,sign
|
|
AUTHOR
|
Paul Barry (pbarry(AT)wit.ie), Feb 10 2003
|
|
|
Search completed in 0.002 seconds
|