|
Search: id:A080872
|
|
|
| A080872 |
|
a(n)*a(n+3) - a(n+1)*a(n+2) = 4, given a(0)=a(1)=1, a(2)=5. |
|
+0
5
|
|
| 1, 1, 5, 9, 49, 89, 485, 881, 4801, 8721, 47525, 86329, 470449, 854569, 4656965, 8459361, 46099201, 83739041, 456335045, 828931049, 4517251249, 8205571449, 44716177445, 81226783441, 442644523201, 804062262961, 4381729054565
(list; graph; listen)
|
|
|
OFFSET
|
0,3
|
|
|
FORMULA
|
G.f.: (-x^3 - 5*x^2 + x + 1)/(x^4 - 10*x^2 + 1)
a(n)=(3+sqrt(3))/12*(sqrt(3)-sqrt(2))^n+(3-sqrt(3))/12*(-sqrt(3)+sqrt(2))^n+(3+sqrt(3))/12*(sqrt(3)+sqrt(2))^n+(3-sqrt(3))/12*(-sqrt(3)-sqrt(2))^n [From Richard Choulet (richardchoulet(AT)yahoo.fr), Dec 03 2008]
a(n+4)=10*a(n+2)-a(n) [From Richard Choulet (richardchoulet(AT)yahoo.fr), Dec 04 2008]
|
|
CROSSREFS
|
Cf. A080871, A080873, A080874, A080875.
Bisections are A001079 and A072256.
Sequence in context: A088974 A105182 A100457 this_sequence A000324 A123817 A124421
Adjacent sequences: A080869 A080870 A080871 this_sequence A080873 A080874 A080875
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Paul D. Hanna (pauldhanna(AT)juno.com), Feb 22 2003
|
|
|
Search completed in 0.002 seconds
|
