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Search: id:A080924
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| A080924 |
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Jacobsthal gap sequence. |
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+0
3
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| 0, 1, 3, 1, 15, 1, 63, 1, 255, 1, 1023, 1, 4095, 1, 16383, 1, 65535, 1, 262143, 1, 1048575, 1, 4194303, 1, 16777215, 1, 67108863, 1, 268435455, 1, 1073741823, 1, 4294967295, 1, 17179869183, 1, 68719476735, 1, 274877906943, 1, 1099511627775, 1
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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Inverse binomial transform of A080925
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FORMULA
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a(2n)=3*A001045(2n)=3*A002450(n)=4^n-1 a(2n+1)=1
a(n)=(2^n-2(-1)^n+(-2)^n)/2; G.f.: x(1+4x)/((1+x)(1+2x)(1-2x)); E.g.f. : (exp(2x)-2exp(-x)+exp(-2x))/2. - Paul Barry (pbarry(AT)wit.ie), May 16 2003
a(n)=(2^n-2(-1)^n+(-2)^n)/2; G.f.: (x(1+4x)/((1+x)(1-4x^2)); E.g.f.: (exp(2x)-2exp(-x)+exp(-2x))/2. - Paul Barry (pbarry(AT)wit.ie), May 19 2003
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CROSSREFS
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Cf. A001045, A002450, A080926, A080927.
Sequence in context: A101820 A055301 A141459 this_sequence A128042 A108083 A163239
Adjacent sequences: A080921 A080922 A080923 this_sequence A080925 A080926 A080927
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KEYWORD
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easy,nonn
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AUTHOR
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Paul Barry (pbarry(AT)wit.ie), Feb 26 2003
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