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Search: id:A081358
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| A081358 |
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Expansion of log((1+x)/(1-x))/(2(1-x)). |
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+0 5
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| 0, 1, 2, 8, 32, 184, 1104, 8448, 67584, 648576, 6485760, 74972160, 899665920, 12174658560, 170445219840, 2643856588800, 42301705420800, 740051782041600, 13320932076748800, 259500083163955200, 5190001663279104000
(list; graph; listen)
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OFFSET
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0,3
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COMMENT
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Number of cycles of odd cardinality in all permutations of [n]. Example: a(3)=8 because among (1)(2)(3), (1)(23), (12)(3), (13)(2), (132), (123) we have eight cycles of odd length. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Aug 12 2004
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REFERENCES
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I. P. Goulden and D. M. Jackson, Combinatorial Enumeration, Wiley, N.Y., 1983, Exercise 3.3.13
B. A. Kuperschmidt, ... And free lunch for all. A review of Bruce C. Berndt's Ramanujan's notebooks, J. Nonlinear Math. Phys., 7 (2000), R7-R37. MR 2002d:33024.
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LINKS
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B. A. Kuperschmidt, ... And free lunch for all.
B. A. Kuperschmidt, Journal of Non linear Mathematical Physics 2000 v.7 no.2, A Review of Bruce C.Berndt's Ramanujan's Notebooks parts I-V
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FORMULA
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E.g.f.: log((1+x)/(1-x))/(2(1-x)). a(n) = n! sum[ k=0..n, k odd ] 1/k.
a(n) = n!/2*(Psi(ceil(n/2)+1/2)+gamma+2*ln(2)). - Vladeta Jovovic (vladeta(AT)Eunet.yu), Oct 20 2003
a(n) = n!*Sum_{k=1..n} (-1)^(k+1)*2^(k-1)*binomial(n, k)/k. - Vladeta Jovovic (vladeta(AT)Eunet.yu), Aug 12 2005
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PROGRAM
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(PARI) a(n)=if(n<1, 0, n!*polcoeff(log(1+2/(-1+1/(x+x*O(x^n))))/(1-x)/2, n))
(PARI) {a(n)=if(n<0, 0, n!*sum(k=1, n, (k%2)/k))} /* Michael Somos Sep 19 2006 */
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CROSSREFS
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Cf. A049034(n)=a(2n+1).
Sequence in context: A081561 A009753 A141202 this_sequence A048855 A062797 A134751
Adjacent sequences: A081355 A081356 A081357 this_sequence A081359 A081360 A081361
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KEYWORD
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nonn
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AUTHOR
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Michael Somos, Mar 18 2003
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