0,1
a(3)=4 because A033949(3)=15 and 4^2=16==1 mod 15 is the first integer to do so.
(PARI) for (n=3, 100, for (j=2, n-2, if (j^2%n==1, print1(j", "); break)))
Cf. A033949.
Sequence in context: A107431 A023859 A096457 this_sequence A069918 A075380 A078439
Adjacent sequences: A082565 A082566 A082567 this_sequence A082569 A082570 A082571
nonn
Jon Perry (perry(AT)globalnet.co.uk), May 06 2003
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