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Search: id:A082691
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| A082691 |
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a(1)=1, a(2)=2, then if 3*2^k-1 first terms are a(1),a(2),.........,a(3*2^k - 1) we have the 3*2^(k+1)-1 first terms as : a(1),a(2),.........,a(3*2^k - 1),a(1),a(2),.........,a(3*2^k - 1),a(3*2^k-1)+1. |
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+0
2
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| 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 5, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 5, 6, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 5, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3, 4, 5, 6, 7, 1, 2, 1, 2, 3, 1, 2, 1, 2, 3
(list; graph; listen)
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OFFSET
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1,2
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COMMENT
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Consider the subsequence b(k) such that a(b(k))=1. Then 3k-b(k)=A063787(k+1)
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EXAMPLE
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To construct the sequence : start with (1, 2) concatenate those 2 terms gives (1,2,1,2). Add 3, gives the first 5 terms : (1,2,1,2,3). Concatenate those 5 terms gives : (1,2,1,2,3,1,2,1,2,3). Add 4, gives the first 11 terms : (1,2,1,2,3,1,2,1,2,3,4) etc.
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CROSSREFS
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Cf. A082691 (partial sums).
Sequence in context: A106036 A007001 A094917 this_sequence A036043 A128628 A098053
Adjacent sequences: A082688 A082689 A082690 this_sequence A082692 A082693 A082694
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KEYWORD
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nonn
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AUTHOR
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Benoit Cloitre (benoit7848c(AT)orange.fr), Apr 12 2003
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