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Search: id:A082758
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| A082758 |
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Sum of the squares of the trinomial coefficients (A027907). |
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+0 4
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| 1, 3, 19, 141, 1107, 8953, 73789, 616227, 5196627, 44152809, 377379369, 3241135527, 27948336381, 241813226151, 2098240353907, 18252025766941, 159114492071763, 1389754816243449, 12159131877715993, 106542797484006471
(list; graph; listen)
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OFFSET
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0,2
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COMMENT
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a(n) = T(2n,2n) = coefficient of x^(2n) in (1+x+x^2)^(2n), T is the trinomial triangle A027907; Integral representation : a(n) = 1/Pi Integral[(1+2x)^(2n)/Sqrt[1-x^2],{x,-1, 1}], i.e. a(n) is the moment of order 2n of the random variable 1+2X, where the distribution of X is an arcsin law on the interval (-1,1). - Nour-Eddine Fahssi (fahssin(AT)yahoo.fr), Jan 22 2008
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FORMULA
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a(n) = Sum[ T(n, k)^2, {k, 0, n} ] where T(n, k) = trinomial coefficients (A027907).
a(n)=sum(k=0, n, binomial(2*n-k, k)*binomial(2*n, k)) - Benoit Cloitre (benoit7848c(AT)orange.fr), Jul 30 2003
G.f.: (1/sqrt(1+2x-3x^2)+1/sqrt(1-2x-3x^2))/2 (with interpolated zeros) - Paul Barry (pbarry(AT)wit.ie), Jan 04 2005
a(n)=sum{k=0..n, C(2n,2k)*C(2k,k)}=sum{k=0..n, C(n+k,2k)*C(2n,n+k)}; [From Paul Barry (pbarry(AT)wit.ie), Dec 16 2008]
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PROGRAM
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(PARI) a(n)=sum(k=0, n, binomial(2*n-k, k)*binomial(2*n, k))
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CROSSREFS
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Bisection of A002426.
Adjacent sequences: A082755 A082756 A082757 this_sequence A082759 A082760 A082761
Sequence in context: A074559 A027314 A025571 this_sequence A110525 A058859 A095002
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KEYWORD
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easy,nonn
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AUTHOR
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Emanuele Munarini (munarini(AT)mate.polimi.it), May 21 2003
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