|
Search: id:A083567
|
|
|
| A083567 |
|
Let B(n) be the number of binary digits in n. This is the sequence of positive integers n such that 2B(n)=B(n^2). |
|
+0 1
|
|
| 21, 37, 42, 45, 53, 69, 73, 74, 81, 83, 84, 90, 106, 133, 137, 138, 141, 146, 148, 155, 161, 162, 165, 166, 168, 177, 180, 211, 212, 261, 265, 266, 269, 273, 274, 276, 281, 282, 289, 291, 292, 295, 296, 299, 310, 321, 322, 324, 330, 332, 336, 354, 359, 360
(list; graph; listen)
|
|
|
OFFSET
|
1,1
|
|
|
COMMENT
|
This is the sequence of n such that the average of ones in binary expansion of n is the same of the average of ones in binary expansion of n^2. Conjecture.
The counting function p(n) p(n)=c n/log n + o(n/log n).
|
|
REFERENCES
|
G. Melfi, On a family of positive integer sequences, in preparation.
|
|
EXAMPLE
|
a(1)=21 because 21=(10101) and 441=(110111001), and no smaller integer has the property that 2B(n)=B(n^2).
|
|
CROSSREFS
|
Cf. A077436.
Sequence in context: A043751 A043759 A043768 this_sequence A109211 A050782 A061906
Adjacent sequences: A083564 A083565 A083566 this_sequence A083568 A083569 A083570
|
|
KEYWORD
|
easy,nonn
|
|
AUTHOR
|
Giuseppe Melfi (Giuseppe.Melfi(AT)unine.ch), Jun 13 2003
|
|
|
Search completed in 0.002 seconds
|