|
Search: id:A083662
|
|
|
| A083662 |
|
a(n)=a([n/2])+a([n/4]), n>0. a(0)=1. |
|
+0 2
|
|
| 1, 2, 3, 3, 5, 5, 5, 5, 8, 8, 8, 8, 8, 8, 8, 8, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 21, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
FORMULA
|
For n>0, a(n) = F([log(n)/log(2)]+3) where F(k) denotes the k-th Fibonacci number. For n>=3, F(n) appears 2^(n-3) times. More generally, if p is an integer>1 and a(n)=a([n/p])+a([n/p^2]), n>0, a(0)=1, then for n>0, a(n) = F([log(n)/log(p)]+3).
|
|
PROGRAM
|
(PARI) a(n)=if(n<1, n==0, a(n\2)+a(n\4))
|
|
CROSSREFS
|
Cf. A088468.
Sequence in context: A072923 A131922 A113730 this_sequence A130149 A053046 A066658
Adjacent sequences: A083659 A083660 A083661 this_sequence A083663 A083664 A083665
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Benoit Cloitre (benoit7848c(AT)orange.fr), Oct 05 2003
|
|
|
Search completed in 0.002 seconds
|