Logo

Greetings from The On-Line Encyclopedia of Integer Sequences!

Hints

Search: id:A083697
Displaying 1-1 of 1 results found. page 1
     Format: long | short | internal | text      Sort: relevance | references | number      Highlight: on | off
A083697 2^(2^n-1) * Fibonacci(2^n). +0
2
1, 2, 24, 2688, 32342016, 4677882957791232, 97861912906883207538212742365184, 42829440312913272520181533609472356498655100482256687829780267008 (list; graph; listen)
OFFSET

0,2

COMMENT

A083696(n)/a(n) converges to sqrt(5). a(n)=2*a(n-1)*A083696(n-1). Similar to A081460: a(n) is the denominator of the same mapping f(r)=(1/2)(r+5/r) but with initial value r=1.

FORMULA

a(n)=Sum[Prod(2^n-k), (k=0, 2r)]5^r/(2r+1)!, (r=0, 2^n-1).

MATHEMATICA

Table[Sum[Product[2^n - k, {k, 0, 2*r}]k^r/(2*r + 1)!, {r, 0, 2^n - 1}], {n, 0, 8}]

CROSSREFS

Equals A058635(n) * A058891(n).

Sequence in context: A163086 A053995 A007079 this_sequence A110131 A112332 A101339

Adjacent sequences: A083694 A083695 A083696 this_sequence A083698 A083699 A083700

KEYWORD

easy,nonn

AUTHOR

Mario Catalani (mario.catalani(AT)unito.it), May 22 2003

EXTENSIONS

The next term is too large to include.

Better description from Ralf Stephan, Aug 29 2004

page 1

Search completed in 0.002 seconds

Lookup | Welcome | Find friends | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
More pages | Superseeker | Maintained by N. J. A. Sloane (njas@research.att.com)

Last modified November 25 20:09 EST 2009. Contains 167514 sequences.


AT&T Labs Research