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a(4)=a(5)=a(6) = 9 because there are (exactly) six consecutive 9's occurring
with starting index A049522(4)=A049522(5)=A049522(6) = 763 and there are no
runs of 4, 5, 6, or more consecutive equal digits having a smaller starting
index. The first occurrence of a run of at least seven consecutive equal digits
occurs at starting index A049522(7) = 710101. The run consists of exactly
seven 3's so a(7) = 3 [=A084144(7)] and also A049523(7) = 710101.
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