1,1

n+sum_of_digits[n] as square in A066564

a(3)=121 because 121+(1+2+1)=125=5^3.

Cf. A066564.

Adjacent sequences: A084658 A084659 A084660 this_sequence A084662 A084663 A084664

Sequence in context: A137567 A053529 A005442 this_sequence A112294 A073511 A108704

easy,nonn,base

Zak Seidov (zakseidov(AT)yahoo.com), Jun 29 2003