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A088435 1/2 + half of the (n+1)-st component of the continued fraction expansion of sum(k>=1,1/3^(2^k)). +0
2
3, 2, 2, 1, 2, 3, 2, 1, 3, 2, 1, 2, 2, 3, 2, 1, 3, 2, 2, 1, 2, 3, 1, 2, 3, 2, 1, 2, 2, 3, 2, 1, 3, 2, 2, 1, 2, 3, 2, 1, 3, 2, 1, 2, 2, 3, 1, 2, 3, 2, 2, 1, 2, 3, 1, 2, 3, 2, 1, 2, 2, 3, 2, 1, 3, 2, 2, 1, 2, 3, 2, 1, 3, 2, 1, 2, 2, 3, 2, 1, 3, 2, 2, 1, 2, 3, 1, 2, 3, 2, 1, 2, 2, 3, 1, 2, 3, 2, 2, 1, 2, 3, 2, 1, 3 (list; graph; listen)
OFFSET

1,1

COMMENT

To construct the sequence use the rule : a(1)=3, then a(a(1)+a(2)+...+a(n)+1)=2+(-1)^n and fill in any undefined place with 2.

FORMULA

a(n)=(1/2)*(1+A004200(n+1)); a(a(1)+a(2)+...+a(n)+1)=2+(-1)^n

EXAMPLE

Example to illustrate the comment : a(a(1)+1)=a(4)=2+(-1)^1=1 and a(2), a(3) are undefined. The rule forces a(2)=a(3)=2.

CROSSREFS

Cf. A088431.

Sequence in context: A065310 A016558 A090341 this_sequence A074976 A068448 A054081

Adjacent sequences: A088432 A088433 A088434 this_sequence A088436 A088437 A088438

KEYWORD

nonn

AUTHOR

Benoit Cloitre (benoit7848c(AT)orange.fr), Nov 08 2003 Ben.

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Last modified August 29 17:54 EDT 2008. Contains 143238 sequences.


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