0,4

Recurrence; a(n+2) = F(n) a(n+1) + F(n+1) a(n) where F(n) = Fibonacci number (A000045)

a[n_] := a[n] = Fibonacci[n - 2]a[n - 1] + Fibonacci[n - 1]a[n - 2] a[0] = 1 a[1] = 1

Sequence in context: A132880 A019537 A046911 this_sequence A132852 A055790 A020131

Adjacent sequences: A089124 A089125 A089126 this_sequence A089128 A089129 A089130

nonn

Emanuele Munarini (munarini(AT)mate.polimi.it), Dec 05 2003